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96 lines
2.6 KiB
Plaintext
96 lines
2.6 KiB
Plaintext
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3 years ago
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foreign class Random {
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construct new() {
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seed_()
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}
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construct new(seed) {
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if (seed is Num) {
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seed_(seed)
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} else if (seed is Sequence) {
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if (seed.isEmpty) Fiber.abort("Sequence cannot be empty.")
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// TODO: Empty sequence.
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var seeds = []
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for (element in seed) {
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if (!(element is Num)) Fiber.abort("Sequence elements must all be numbers.")
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seeds.add(element)
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if (seeds.count == 16) break
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}
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// Cycle the values to fill in any missing slots.
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var i = 0
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while (seeds.count < 16) {
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seeds.add(seeds[i])
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i = i + 1
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}
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seed_(
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seeds[0], seeds[1], seeds[2], seeds[3],
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seeds[4], seeds[5], seeds[6], seeds[7],
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seeds[8], seeds[9], seeds[10], seeds[11],
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seeds[12], seeds[13], seeds[14], seeds[15])
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} else {
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Fiber.abort("Seed must be a number or a sequence of numbers.")
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}
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}
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foreign seed_()
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foreign seed_(seed)
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foreign seed_(n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12, n13, n14, n15, n16)
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foreign float()
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float(end) { float() * end }
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float(start, end) { float() * (end - start) + start }
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foreign int()
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int(end) { (float() * end).floor }
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int(start, end) { (float() * (end - start)).floor + start }
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sample(list) {
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if (list.count == 0) Fiber.abort("Not enough elements to sample.")
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return list[int(list.count)]
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}
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sample(list, count) {
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if (count > list.count) Fiber.abort("Not enough elements to sample.")
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var result = []
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// The algorithm described in "Programming pearls: a sample of brilliance".
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// Use a hash map for sample sizes less than 1/4 of the population size and
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// an array of booleans for larger samples. This simple heuristic improves
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// performance for large sample sizes as well as reduces memory usage.
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if (count * 4 < list.count) {
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var picked = {}
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for (i in list.count - count...list.count) {
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var index = int(i + 1)
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if (picked.containsKey(index)) index = i
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picked[index] = true
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result.add(list[index])
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}
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} else {
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var picked = List.filled(list.count, false)
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for (i in list.count - count...list.count) {
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var index = int(i + 1)
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if (picked[index]) index = i
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picked[index] = true
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result.add(list[index])
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}
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}
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return result
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}
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shuffle(list) {
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if (list.isEmpty) return
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// Fisher-Yates shuffle.
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for (i in 0...list.count - 1) {
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var from = int(i, list.count)
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var temp = list[from]
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list[from] = list[i]
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list[i] = temp
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}
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}
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}
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